A hexagon with sides of length 2, 7, 2, 11, 7, 11 is inscribed in a circle. Find the radius of the circle.

*As suggested, *if* it matters, you may assume that the sides listed are given in order*

assuming the sides are in the order given

(graph paper & compas help to visualize this)

the top and bottom of the hexagon are the sides with length 7

which are parallel. Therefore you also have an inscribed

RECTANGLE of width 7, length unknown. Draw a perpendicular

from the unknown length to the point where the 2 length side

touches the circle (either one) You now have 2 right triangles,

1 with hypotenuse of 2, the other with hypotenuse of 11.

Use pythagorean theorem to get the unknown length of the

rectangle. A third right triangle with hypotenuse from the center

of this rectangle to the point on the circle where 2 and 7 meet.

Its hypotenuse is the radius. I get sqrt 42 ~6.48

If I did this right, it seems to be more accurate since loss of

precision of all those nasty trig thingys.