What are the next two numbers in this sequence?
1, 1, 7, 3, 23, 23, 111, 15, 351, 415, __, __

(In reply to re: The numbers I was looking for by Erik O.)

From Erik O's previous post....

A =   1 = 1
B =   1 = 1
C = 111 = 7
D =  11 = 3

A' =   10111 =  23
B' =   10111 =  23
C' = 1101111 = 111
D' =    1111 =  15

A'' =   101011111 =  351
B'' =   110011111 =  415
C'' = 11100111111 = 1855 - correct numbers
D'' =   100111111 =  319 - as per Brian

To get A, B & C, refer to Erik's post here. To get D you need to use both B & C. Start by erasing the 2 left-most numbers from C. Then you need to add a number from B to the left of what's left. For D, you add the 1st number from the left of B. For D' it's the 2nd, and for D'' it's the 3rd.

So C is 111. Take away two 1's from the left, then add the 1st number from B which is 1. That leaves you with 11.

C' is 1101111. Minus the 1st two 1's leaves you with 01111. Plus the 2nd number from B' is 0. That leaves you with 001111, which is the same as 1111.

C'' is 11100111111. Minus the 1st two 1's leaves you with 100111111. Plus the 3rd number from B'' which is 0, leaves you with the same thing.

Howz that for a crazy solution?

Posted by Danny on 2004-06-11 09:03:39