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Mixing Paint (Posted on 2004-06-06) Difficulty: 2 of 5
A painter has a gallon tin (eight pints) contianing six pints of yellow paint and another gallon tin containing four pints of blue paint. He wants to mix the paints together so he can paint a room green. The shade of green in all the containers at the end must be the same.

The two tins are different shapes (though the both will hold exactly a gallon) and they are not symmetric shapes, so it is not possible to tell if they are, say, half full by tilting them at an angle. The painter cannot make marks on the tins either .

He needs all ten pints to paint the room, unfortunately, he doesn't have a mixing vessel large enough to hold all the paint - the only other container he has is a pint glass.

By pouring paint back and forth, mix the paint correctly using just these containers.

See The Solution Submitted by Brian Smith    
Rating: 3.0000 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution Solution (spoiler) | Comment 1 of 3

Designate the number of pints in each container, followed by the percent blue in parentheses.   So the initial conditions are:
6 (0), 4 (100), 0    
5 (0), 4 (100), 1(0)
5 (0), 5 (80), 0
4 (0), 5 (80), 1(0)
8 (40), 1 (80), 1(0)
8 (40), 2 (40), 0

  Posted by Larry on 2004-06-06 13:02:02
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