Place nine different digits (from 0-9) into a 3x3 grid, such that the eight sums formed by the three rows, three columns and two diagonals are consecutive numbers.
Apparently (I'm not smart enough to prove it) you need a gap in the numbers in order to have a square of this type. For all the integers to be non-zero, you have to allow at least a maximum of 10, rather than a maximum of 9, as Brian Smith's puzzle requires.
7 1 6
9 8 4
2 10 5
column 3 = 15
diagonal 2 = 16
row 3 = 17
column 1 = 18
column 2 = 19
diagonal 1 = 20
row 2 = 21
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Posted by Penny
on 2004-06-19 20:33:49 |
9 nonzero integers (variation on the puzzle)
