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 Bird on a Wire (Posted on 2004-06-07)
A telephone wire stretched tight between two poles placed ten meters apart is a favorite resting spot for a flock of crows.

Suppose one morning two crows land on the wire, each at a random spot (the probability is uniformly distributed). With a bucket of paint and a brush you mark the stretch of wire between them. A certain length of wire will have been painted.

On average, what length of wire would you expect to have painted? Assume that each bird is a single point along the line, and so has no width.

Suppose instead that a dozen crows landed on the wire, each at an independent, random location, and you painted the stretch of wire between each bird and its nearest neighbor. On average, what total length of wire would you expect to have painted now?

And if a thousand crows landed?

A computer-generated solution could be found, but bonus points will be awarded for a formal proof!

 No Solution Yet Submitted by Sam Rating: 3.7000 (10 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
 re(3): Computer simulation | Comment 11 of 42 |
(In reply to re(2): Computer simulation by Charlie)

While two birds give 3.333333,
Three birds show 3.11806 +/- 0.00804
Four birds show 3.265439 +/- 0.006331
Five show 3.379181 +/- 0.005747
Six show 3.462290 +/- 0.005248

It looks as if from 3 birds onward, it's monotonically increasing.

Edited on June 7, 2004, 4:12 pm
 Posted by Charlie on 2004-06-07 15:38:41

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