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Gonna party like it's 1999 (Posted on 2004-09-12) Difficulty: 1 of 5
Find a solution to:
x1^4 + x2^4 + x3^4 + ... + xn^4 = 1999

where each xy is a distinct integer.

(Or prove that it is impossible).

See The Solution Submitted by SilverKnight    
Rating: 3.2500 (4 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: Answer | Comment 3 of 8 |
(In reply to Answer by Old Original Oskar!)

Read the problem again. It says integers so it includes -1, -2, -3, -4, -5, and -6.


  Posted by np_rt on 2004-09-12 13:14:22
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