8448 is a multiple of 44. Change the two 4s for different odd numbers X and Y, so 8XY8 can be divided by XY. No computers allowed!
(In reply to
answer by K Sengupta)
By the problem, 8XY8 is divisible by XY, so that 8XY8 - 10*(XY) = 8008 is divisible by XY.
Now, 8008 = 7*8*11*13, and accordingly two digit odd numbers that are factors of 8008 are 11, 13, 77, 91.
But, XY = 11, 77 violates the provisions of the problem that X!=Y.
Consequently, XY = 13 or 91.
Edited on August 1, 2022, 7:37 am
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