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Prime clock (Posted on 2004-08-01) Difficulty: 3 of 5
Given a clock, rearrange six consecutive numbers on its face, so the sum of every pair of adjacent numbers is a prime.

  Submitted by Federico Kereki    
Rating: 3.7500 (8 votes)
Solution: (Hide)
There are two solutions, both reordering numbers 5 to 10:

1 2 3 4 7 10 9 8 5 6 11 12
1 2 3 4 9 10 7 6 5 8 11 12

Comments: ( You must be logged in to post comments.)
  Subject Author Date
Solutionnot that we need another computer solutionvectorboy2004-08-12 17:06:32
SolutionSolutionEmma2004-08-06 20:56:02
SolutionSolutionmatt2004-08-02 13:51:49
SolutionSolutionGaolman2004-08-02 11:17:02
re: No SubjectPenny2004-08-02 06:47:42
SolutionNo Subjectneshal2004-08-02 05:25:23
No SubjectIsabel2004-08-02 04:17:34
re: A question....Isabel2004-08-02 04:00:52
A question....Isabel2004-08-02 03:57:55
re: maybePenny2004-08-02 00:32:20
maybesharon reese2004-08-02 00:12:57
not a solutionsharon reese2004-08-01 23:55:45
solved!sharon reese2004-08-01 23:26:52
SolutionAnother computer solutionPenny2004-08-01 14:30:36
SolutionThe computer methodCharlie2004-08-01 11:29:46
Solutiontrial & error solutionDanny2004-08-01 10:41:13
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