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Factorials everywhere (Posted on 2004-08-16) Difficulty: 3 of 5
The equation a!b!=c! is trivial if we allow a or b to be 0 or 1.

However, adding that 1<a<b<c, also allows trivial solutions: which? What condition should be added to disallow such solutions?

Finally, adding that condition, can you find any solution to the problem?

See The Solution Submitted by Federico Kereki    
Rating: 2.6000 (5 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
SOLUTION++++ | Comment 2 of 6 |
b=a!-1 does it

e.g. a=4 b=23 c= 4!*23!=24!

infinite number of solutions

ady
  Posted by Ady TZIDON on 2004-08-16 10:30:42
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