The equation a
! is trivial if we allow a
to be 0 or 1.
However, adding that 1<a<b<c, also allows trivial solutions: which? What condition should be added to disallow such solutions?
Finally, adding that condition, can you find any solution to the problem?
(In reply to More trivial solutions
If solutions of the form a!=(b+1)(b+2)... are considered trivial, then all solutions are trivial, as this must be the case for any a!b!=c!, as in Bryan's solution.
Posted by Charlie
on 2004-08-16 12:25:32