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Summing inverses (Posted on 2004-08-19) Difficulty: 3 of 5
What's the limit, as n→∞, of 1/(n+1)+1/(n+2)+1/(n+3)+...+1/(2n)?

See The Solution Submitted by Federico Kereki    
Rating: 4.0000 (5 votes)

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An easy way to bound the answer Comment 18 of 18 |
(In reply to re(3): Reason why sum of limits is not same as limit as sums by Bob)

The problem with taking the limit individually and then summing, is as n goes to infinity, there are an infinite number of terms. So in effect, you're trying to multiply zero by infinity.

If all the terms were 1/n, the sum would be 1. If all the terms were 1/2n, the sum would be 1/2. So the answer must lie somewhere in between.

  Posted by Gamer on 2008-09-29 17:12:05

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