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 Baseball Anyone? (Posted on 2004-11-03)
The Peytonville Peacocks and the Adenville Aardvarks have each played the same number of games so far this season.

The Peacocks have a .664 average, and the Aardvarks have won 70 games. Which team is ahead?

Note that each team plays 162 games in a season, and that the team's average is the number of games won divided by the number of games played rounded off to three decimal places.

 No Solution Yet Submitted by SilverKnight Rating: 2.0000 (3 votes)

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 Solution Using a Slightly Different Aprproach | Comment 3 of 6 |

We know the number of total games played by each team is the same.  We also know that the total games played must be greater than 70 and less than or equal to 162.  The most important fact is that one team won precisely 66.4% of their games.  The only integer between 71 and 162 that when multiplied by 66.4% is an integer is the number 125.  Therefore, each team played 125 games.  The Aardvarks won 70 (as stated in the problem) and the Peacocks won 125 x .664 = 83.

 Posted by Gordon Steel on 2004-11-03 17:56:20

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