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 Year by Year (Posted on 2004-11-23)
Consider N=2004^2004.

1) What are the first 3 digits of N?

2) What are the last 3 digits of N?

 Submitted by SilverKnight Rating: 2.3333 (6 votes) Solution: (Hide) answer: http://www.stetson.edu/departments/mathcs/events/mathcontest/1996/index.shtml

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 Subject Author Date Solution To Part II of N = 1996^1996 K Sengupta 2007-10-18 06:31:33 Solution To Part II K Sengupta 2007-10-18 06:28:07 Solution To Part I K Sengupta 2007-10-18 06:27:12 cool... sragen 2004-11-30 05:41:36 Or use a really big calculator... Jer 2004-11-23 17:33:37 re: alternate method (not tested) Charlie 2004-11-23 16:28:43 alternate method (not tested) Larry 2004-11-23 15:35:19 solution (spoiler) Charlie 2004-11-23 15:11:39
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