 All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars  perplexus dot info  Exponential Difficulties 2 (Posted on 2004-11-27) What's the least positive integer, n, having the following properties:
• n = (a^2)/2
• n = (b^3)/3
• n = (c^5)/5
(where a, b, and c are integers)

 See The Solution Submitted by SilverKnight Rating: 4.0000 (5 votes) Comments: ( Back to comment list | You must be logged in to post comments.) 2 out of 3; a start | Comment 1 of 9

Well, n=0 works but it's not positive (unless zero positive is "the least positive")

Otherwise, a must be a power of 2; b a power of 3; c a power of 5

((3*c^5)/5)^(1/3) = b
((2*c^5)/5)^(1/2) = a

Need to find a value for c such that both of the above equations yield integers.

I'm not sure how much this helps, probably not very much, but here are some values where 2 of the 3 original conditions are true (ie 1 of the 2 above equations):

a=12   b=6   n=72
a=96   b=24  n=4608
a=324  b=54   n=52488
a=200  c=10   n=20000
a=6400  c=40  n=20480000
b=1125  c=75  n=474609375
a=48600  c=90  n=1180980000

Edited on November 27, 2004, 5:07 pm

Edited on November 27, 2004, 5:08 pm
 Posted by Larry on 2004-11-27 16:59:21 Please log in:

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