Is there any integer multiple of N=2^2004 that includes no zeroes in its decimal representation?

A straightforward generalization of Spirit of '76 allows us to assert that, for every k, there is a k-digit multiple of 2^k, written exclusively with 7s and 6s.  Now substitute k = 2004.

Posted by Nick Hobson on 2004-08-27 17:03:45