Take any odd number and square it. It will invariably be a multiple of 8 plus 1. So (odd)^2=8n+1 where n is an integer. Show why this is always so. Also show what the pattern for n is.
X²  1 = (X + 1)(X  1)
If X is odd (X = 2a + 1), then (X + 1) and (X  1) are even
X + 1 = 2a +2
X  1 = 2a
(X + 1)(X  1) = (2a + 2)(2a) =
4a² + 4a = 4a(a + 1). Since either a or (a + 1) is even, a(a + 1) is even and 4a(a + 1) is divisible by 8
To show the triangle number connection, it still can be shown that 4a² + 4a = 8*T(a)

Posted by TomM
on 20021006 17:52:23 