All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
Square of an Odd (Posted on 2002-10-06) Difficulty: 2 of 5
Take any odd number and square it. It will invariably be a multiple of 8 plus 1. So (odd)^2=8n+1 where n is an integer. Show why this is always so. Also show what the pattern for n is.

See The Solution Submitted by martyn    
Rating: 3.1333 (15 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Some Thoughts hmm.. | Comment 15 of 20 |

i saw the looked over complicated...haha =0)

odd number = (2k + 1)... k belonging to Integer..

(2k+ 1)^2 = 4k^2 + 4k + 1

4k^2 + 4k = 8n
k^2 + k = n
k(k+1) = 2n

the rest was the same...k's either even or odd..
this has prolly been posted already..but..*shrug* i'm too lazy to read thru all of the posts ^^ haha

ignore this if you wanna.

  Posted by Amon on 2005-05-04 02:46:33
Please log in:
Remember me:
Sign up! | Forgot password

Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (5)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Copyright © 2002 - 2020 by Animus Pactum Consulting. All rights reserved. Privacy Information