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Square of an Odd (Posted on 2002-10-06) Difficulty: 2 of 5
Take any odd number and square it. It will invariably be a multiple of 8 plus 1. So (odd)^2=8n+1 where n is an integer. Show why this is always so. Also show what the pattern for n is.

See The Solution Submitted by martyn    
Rating: 3.1333 (15 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: Alternate Approach | Comment 8 of 20 |
(In reply to Alternate Approach by TomM)

This is exactly the approach I used. :)
  Posted by Gamer on 2003-03-12 14:06:00

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