Take any odd number and square it. It will invariably be a multiple of 8 plus 1. So (odd)^2=8n+1 where n is an integer. Show why this is always so. Also show what the pattern for n is.

(In reply to Alternate Approach by TomM)

This is exactly the approach I used. :)

Posted by Gamer on 2003-03-12 14:06:00