Take any odd number and square it. It will invariably be a multiple of 8 plus 1. So (odd)^2=8n+1 where n is an integer. Show why this is always so. Also show what the pattern for n is.
All odd numbers are of the form 4x+1 or 4x+3. We have two cases.
The pattern for n is triangular numbers.
Posted by Math Man
on 2013-06-10 16:51:54