All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Cubeless? (Posted on 2004-08-29) Difficulty: 3 of 5
Prove that for any positive integer n, there exists at least one multiple of 5^n that doesn't have any perfect cube digits (0, 1, or 8) in its decimal representation.

See The Solution Submitted by Federico Kereki    
Rating: 3.4000 (5 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Understandable | Comment 5 of 7 |

I am guessing that the actual solution has not been posted by anyone yet.  If it has been posted, I didn't get it.

I'm curious as to how this can be proven. 

Still just hoping I understand the answer.


  Posted by Bruce Brantley on 2004-09-20 10:45:26
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (14)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information