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Perfect square? (
Posted on 20040723
)
Find all integer solutions of y² = x³  432.
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Submitted by
Nick Hobson
Rating:
3.0000
(6 votes)
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Short solution
 Comment 2 of 12 
If x³=y²+432, then (6x)³= 6³(y²+432)= (y+36)³(y36)³, so (6x)³+(y36)³=(y+36)³, which by Fermat's last theorem, is only possible some term is 0, so we need y=±36.
Posted by
Oskar
on 20040723 13:40:31
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