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 Two Crescents (Posted on 2004-08-11)
Given a right triangle, draw the three following semicircles:
1. The semicircle with diameter formed by one of the legs and extending away from the triangle.
2. The semicircle with diameter formed by the other leg and extending away from the triangle.
3. The semicircle with diameter formed by the hypotenuse and extending towards the triangle.

Prove that the area of the two crescents (shown in RED and BLUE) formed by the three semicircles equals the area of the triangle.

 No Solution Yet Submitted by ThoughtProvoker Rating: 3.2000 (10 votes)

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 Simple | Comment 6 of 15 |
Call the sides a, b and c, with a²=b²+c². The total area equals Triangle+πb²/4+πc²/4, or Crescents+πa²/4. Using the pythagorean property above, all terms with π cancel out, and we are left with Triangle=Crescents.
 Posted by Federico Kereki on 2004-08-11 10:52:33

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