A round hole is drilled through the center of a spherical solid with a radius (r). The resulting cylindrical hole has height 4 cm.
a)What is the volume of the solid that remains?
b)What is unusual about the answer?
a) If a is the radius of the drilled hole, then r^2 = a^2 + 2^2. If we let a > 0, then r > 2. Therefore, the volume of solid that remains is (4/3)*ð*r^3 or 32*ð/3 cm^3.
b) The answer is independent of the radius r. Although r must be greater than 2.

Posted by Bractals
on 20040821 10:00:48 