All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math > Calculus
Hole in a bead (Posted on 2004-08-21) Difficulty: 4 of 5
A round hole is drilled through the center of a spherical solid with a radius (r). The resulting cylindrical hole has height 4 cm.

a)What is the volume of the solid that remains?

b)What is unusual about the answer?

See The Solution Submitted by Pieater    
Rating: 3.0909 (11 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
No Subject | Comment 11 of 13 |

Vol of sphere = 4/3*pi*2^3.

We assume the radius of sphere to be 2 because the hole drilled has a height of 4 which should equal 2r.

Vol of sphere = 32/3*pi

Vol of cylinder = pi*r^2*4 = 4*pi*r^2.

Volume remaining = 32pi/3 - 4pi*r^2

b). The answer will be ununusual since we can't take into consideration the curvature at the top of the sphere which doesn't account for the radius of the drilled cylindrical hole.

  Posted by Osi on 2004-11-05 09:36:31
Please log in:
Remember me:
Sign up! | Forgot password

Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (8)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Copyright © 2002 - 2019 by Animus Pactum Consulting. All rights reserved. Privacy Information