This game starts with some noughts and some crosses. You and your opponent take turns removing two shapes, and adding a new one according to this rule: if the shapes are identical, add a nought; otherwise, add a cross. When only one shape remains, you win if it's a nought, and lose if it's a cross.

Is there a winning strategy for any of the players? How should you play?

OK, So if in either case, There are an even number of O's the first player will win. If an odd number of O's occurs it will lead to the second player's win.

If you would like me to explain my answer, i would be happy to.

I appoligise in advance for if i ether; Stated the exact same solution(Word in word) , or if i cause an argument of somesort due to the fact that my answer is differnt(IF, emphasis on the IF).

Posted by chris on 2005-03-13 06:36:55