Triangle ABC has side AB=AC, and angle BAC = 20 degrees.
D is a point on side AC with AD=BC. Find angle DBC.
Solve this without trigonometry.
I made this diagram using geometer's sketchpad
It didn't yield any insights that led me to a proof, but I did find the angle.
It is 70 degrees.
Posted by Jer
on 2004-09-08 12:40:50