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Red ball... Red ball (Posted on 2002-10-17) Difficulty: 4 of 5
If you take two balls randomly out of a jar of colored balls, there is a 50% chance that the balls will both be red.

What is the total percentage of red balls in the jar?

See The Solution Submitted by levik    
Rating: 3.1538 (13 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution re: Another solution (re: a mathematecally more rigorous solution) Comment 15 of 15 |
(In reply to Another solution (re: a mathematecally more rigorous solution) by Charlie)

I saw this puzzle recently and after solving it at the d2 level went thru solvers posts, since I got two solutions, and the official solution cited only one.

My approach was:  there are r*(r-1)/2 possibilities of choosing 2 red and ALL*(ALL-1)/2 possibilities of choosing ANY 2 marbles.

Comparing twice the former with the latter boils down to

A^2-A+2*r-r^2=0,  resolved as

ALL=.5*(1+sqrt(1+8(r^2-r)))

3,4  and 15,21  fit  getting an integer pair and reaching
a conclusion that there is more than one solution.- actually infinity.

I was relieved to see your post and decided to chip in my humble contribution.


The original puzzle would be politically correct by adding a constraint like "out of a jar  containing no more than 30   colored balls"... etc


  Posted by Ady TZIDON on 2015-08-22 03:34:06
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