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A Different Magic Square (Posted on 2004-10-29) Difficulty: 4 of 5
Take one 1, two 2s, three 3s, four 4s, five 5s, six 6s, seven 7s, and eight 8s and place them in a 6-by-6 grid, one digit per square, such that each row, column, and major diagonal sums to 34.

See The Solution Submitted by Brian Smith    
Rating: 4.2500 (4 votes)

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Some Thoughts Answer Comment 7 of 7 |

One of the arrangements is as follows:

8..4..4..4..6..8
8..8..3..7..3..5
6..4..7..8..7..2
7..5..6..1..8..7
2..6..6..8..5..7
3..7..8..6..5..5


  Posted by K Sengupta on 2007-08-23 14:45:05
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