Triangle ABC is isosceles with AB=AC. Point D is on side AB such that angle BCD is 70 degrees.
Point E is on side AC such that angle EBC is 60 degrees.
Angle ABE equals 20 degrees, and angle DCE equals 10 degrees.
Find angle EDC. Justify your answer.
(In reply to
Not sure why I don't get the same answer by Jils)
"By similar triangles DE=DA/BA."
Isn't it DG = DA/BA, as DG is the one that's horizontal, parallel to BC?

Posted by Charlie
on 20041109 16:06:21 