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Ordering Pairs (Posted on 2004-11-06) Difficulty: 3 of 5
What are the smallest positive integers A, B, C, and D such that A+A > A+B > A+C > B+B > B+C > A+D > C+C > B+D > C+D > D+D ?

Note: Of all solutions, choose the one with the smallest A, then smallest B if there are more than one with the smallest A, etc.

See The Solution Submitted by Brian Smith    
Rating: 3.7500 (4 votes)

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answer Comment 10 of 10 |

The minimum possible solution is (A, B, C, D) = (10, 7, 5, 1)


  Posted by K Sengupta on 2007-03-25 04:11:07
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