All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Up to 35 (Posted on 2004-11-14) Difficulty: 3 of 5
S is a set of N distinct positive integers such that no member of S has a prime factor greater than 35. Let P be the set of products of members of S taken 2 at a time. (For example, if x, y and z are members of S, then xy, xz and yz will be members of P.)

What is the smallest value of N for which it is certain that P contains a perfect square?

  Submitted by Brian Smith    
Rating: 3.5000 (4 votes)
Solution: (Hide)
2^11+1 = 2049
My solution is below. Charlie offers a solution here.

Each member of S can be written as R^2*F, where F has no perfect square factors other than 1. A square in P arrives when two members of S have the same F value. Since there are 11 prime numbers less than 35, there are 2^11 possible F values. And by the pigeon hole principle, if there are 2^11+1 members in S, two must have the same F value which means their product is a perfect square.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
answerK Sengupta2007-12-23 12:09:29
I'm convincedSteve Herman2004-11-15 08:04:54
Scaled Down VersionRichard2004-11-15 00:35:56
SolutionI agree with Charlie and here is why.owl2004-11-14 11:49:51
Hints/TipsAm I seeing all the possibilities? (solution, if I am)Charlie2004-11-14 11:39:09
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (9)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information