Given that 38! = 523,022,617,466,601,111,760,007,224,100,abc,def,gh0,000,000, determine, with a minimum of arithmetical effort, the digits a, b, c, d, e, f, g, and h. No calculators or computers allowed!
I have a meeting in 5 minutes, but I can say that 38! ends in 8 zeroes. 1 for each of 5, 10, 15, 20, 30 and 35 plus 2 for 25. (There are plenty of 2's to go around)
So h=0
and g<>0 (I think <> means 'is not equal to')
Jer

Posted by Jer
on 20041110 14:22:24 