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Missing Digits (Posted on 2004-11-10) Difficulty: 3 of 5
Given that 38! = 523,022,617,466,601,111,760,007,224,100,abc,def,gh0,000,000, determine, with a minimum of arithmetical effort, the digits a, b, c, d, e, f, g, and h. No calculators or computers allowed!

No Solution Yet Submitted by Nick Hobson    
Rating: 2.8000 (5 votes)

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Until I have time | Comment 1 of 7

I have a meeting in 5 minutes, but I can say that 38! ends in 8 zeroes.  1 for each of 5, 10, 15, 20, 30 and 35 plus 2 for 25.  (There are plenty of 2's to go around)

So h=0

and g<>0 (I think <> means 'is not equal to')

-Jer


  Posted by Jer on 2004-11-10 14:22:24
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