Given that 38! = 523,022,617,466,601,111,760,007,224,100,abc,def,gh0,000,000, determine, with a minimum of arithmetical effort, the digits a, b, c, d, e, f, g, and h. No calculators or computers allowed!

(In reply to Until I have time by Jer)

Agreed. And as the product of the digits 1-4 & 6-9 ends in 6, and 1-4 & 6-8 ends in 4....6*6*6*4 gives a 4 for "g"

Posted by Nosher on 2004-11-10 18:48:01