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Missing Digits (Posted on 2004-11-10) Difficulty: 3 of 5
Given that 38! = 523,022,617,466,601,111,760,007,224,100,abc,def,gh0,000,000, determine, with a minimum of arithmetical effort, the digits a, b, c, d, e, f, g, and h. No calculators or computers allowed!

No Solution Yet Submitted by Nick Hobson    
Rating: 2.8000 (5 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: Until I have time | Comment 2 of 7 |
(In reply to Until I have time by Jer)

Agreed. And as the product of the digits 1-4 & 6-9 ends in 6, and 1-4 & 6-8 ends in 4....6*6*6*4 gives a 4 for "g"


  Posted by Nosher on 2004-11-10 18:48:01
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