Simple algebra: His wife's original age is 1/3 his, so if his age is y, her's is 3x. 15 years later, he is twice her age: (y+15)=2(x+15). Substitute 3x for y in the second equation, and solve.
He was 45, she was 15.
|
Posted by Bean
on 2007-01-06 09:20:31 |