How many squares can be drawn on a checkers board, given that these squares should consist of whole black-white squares (the ones that are already painted on the board)?
(In reply to
answer by K Sengupta)
For a n*n board , we know that the total number of squares of any dimension is equal to Sum (i= 1 to n) (i^2)
= n(n+1)(2n+1)/6
A checkerboard is a 8*8 board. So, substituting n= 8, we obtain the required number of squares(of any dimension)
= 8*9*17/6 = 204.
Problem Solution With Explanation
