In Levikland, there are coins worth 1, 2, 5, 10, 20, 50 and 100 perplexii. A has twice as much money as B, who has twice as much as C, who has twice as much as D. How can this be, if everybody has two coins?
Ok, lets start from beginning (usually a good place to start):
D cant have (1+2), because there is no way to get to 24 (3,6,12,24)
D cant have 6 (1+5) or 7 (2+5), following the same logic
If D has 15 (5+10), C has 30 (10+20), B has 60 (50+10), and A has 120 (100+20)
Im a freaking genius
Solution
