In Levikland, there are coins worth 1, 2, 5, 10, 20, 50 and 100 perplexii. A has twice as much money as B, who has twice as much as C, who has twice as much as D. How can this be, if everybody has two coins?
A=2B, B=2C, C=2D => A=8D
A is going to be a large number relatively speaking, or a larger possible with the 2 coin combo, and we can quickly eliminate the 1,2 or 5 coin in the addition to A. Check A=200(100+100), no. Check A=150(100,50), no. Check A=120(100 +20), yes!
A,B,C,D = 120,60,30,15 respectively.
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Posted by Michael
on 2004-11-22 04:32:45 |
Another way or same way a solution anyway.
