In Levikland, there are coins worth 1, 2, 5, 10, 20, 50 and 100 perplexii. A has twice as much money as B, who has twice as much as C, who has twice as much as D. How can this be, if everybody has two coins?

Sorry about the weird title. I was a noob then

Right. Trail and error is useful here.

Working backwards is probably logical. A 1 and a 2 gives you 3. So if that's what D has, then C must have a 5 and a 1 (6). B must therefore have a 10 and a 2 (12). So A has 24. But you can't make 24 with these coins.

How about if D had 15? D=10+5, C=20+10, B=50+10, and A=100+20. D has 15, C has 30, B has 60 and A has 120.

Easy when you know how, which I didn't untill I posted this!

Edited on January 9, 2006, 8:03 am

Edited on December 2, 2007, 5:30 am

Edited on December 2, 2007, 5:31 am

Posted by Paddy on 2005-06-11 11:14:07