The following long division problem is not correct. In fact, none of the digits is what it should be.
Change each of the digits to a different digit so that the arithmetic is correct.
Note that there is no remainder, no leading zeroes, and like digits are not necessarily all changed to the same digit.
The 1 in the 4321 times the divisor makes a 2digit number. That units digit must be at least a 2. So 2 times the divisor is still 2 digits long.
That narrows the divisor to a range of 2049. Dunno how much that helps.

Posted by np_rt
on 20041203 18:30:55 