1) Pick any point O, on the ellipse
2) Construct circle O which intersects the ellipse in four points (A, B, C, D in that order) (I assume this can alway be done.)
3) Construct segments AC and BD. Call the intersection of these two segments Z.
4) Constuct the bisectors of the angles AZB, BZC, CZD, and DZA. (These bisectors are parallel to the axes of the ellipse, but I haven't proven this.)
5) Construct a tangent to the ellipse at point A. Call this line l (I don't know if this can be done.)
6) Construct another tangent to the ellipse which is parallel to l. Call the point of tangency E. (I don't know if this can be done.)
7) Construct segment AE. This line passes through the center of the ellipse. (Unproven)
8) Repeat steps 57 using point B and other point of tangency F.
9) Call the intersection of AE and BF point P. This is the center of the ellipse.
10) Translate the four angle bisectors from step 4 along the vector from Z to P.
I *think* that works, but it is far from a complete solution.
Jer

Posted by Jer
on 20041221 18:08:51 