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Logic Test (Posted on 2004-12-19) Difficulty: 2 of 5
Answer each of the 8 questions with a letter from A to D. The word "answer" in the test refers to YOUR answer, not some hypothetical "best" answer.

After choosing the 8 answers score the test by comparing each question with your answers.

Score 1 point for each question answered correctly, 0 otherwise.

Keep re-taking the test, trying to get the highest possible score. (Of course you must know what the highest possible score is in order to correctly score the last question!)

(1) The next question with the same answer as this one is:
(A) 2 (B) 3 (C) 4 (D) 5

(2) The first question with answer C is:
(A) 1 (B) 2 (C) 3 (D) 4

(3) The last question with answer A is:
(A) 5 (B) 6 (C) 7 (D) 8

(4) The number of questions with answer D is:
(A) 1 (B) 2 (C) 3 (D) 4

(5) The answer occuring the most is: (if tied, first alphabetically)
(A) A (B) B (C) C (D) D

(6) The first question with the same answer as the question following it is:
(A) 2 (B) 3 (C) 4 (D) 5

(7) The answer occuring the least is: (if tied, last alphabetically)
(A) A (B) B (C) C (D) D

(8) The highest possible score on this test is:
(A) 5 (B) 7 (C) 6 (D) 8

See The Solution Submitted by Jim    
Rating: 3.6250 (8 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
The solution according to me | Comment 9 of 13 |

Okay, so here is the solution that I got and how I got it.

1) C

2) A

3) A

4) C

5) A

6) A

7) D

8) D

 

If you start with the last question first, what is the highest score possible, I operated on the premise that 8 is the highest possible. I then read and reread and came up with a couple of basic "rules."

if 2=A, then 6= B and 3=A and 5=A

1 & 2 do not have the same answer

7= D because the answer is B, and if you read the question, the answer occuring the least, last alphabetically if tied. If this question is answered as B, then B and D both have two, and D is last alphabetically

If you follow through and answer the remaining questions, you will see that my solution is accurate, I think. Now, if only the author would post the solution!


  Posted by erin on 2005-03-23 23:19:05
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