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Remainder of One (Posted on 2004-12-29) Difficulty: 4 of 5
Let p be a prime. Let S be a set of (p-1) integers, none of which are divisible by p. Show that some subset of S has a sum that has a remainder of 1 when divided by p.

(The sum of a set is defined as the sum of the elements of the set)

See The Solution Submitted by David Shin    
Rating: 3.8750 (8 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: Yet another Erdos theorem | Comment 5 of 13 |
(In reply to Yet another Erdos theorem by e.g.)

Sorry to be a bother, but I looked over your reference and could not see how it is applicable.  Could you please point out exactly how it applies?  Thanks.
  Posted by Richard on 2004-12-30 17:37:58

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