Four chords of a circle are arranged in such a way that they form a quadrilateral shape, the length of the chords are as follows.

6cm, 7cm, 8cm and 9cm.

what is the area of the circle that will intersect all of the points?

(In reply to

re: Solution (some cheating) by nikki)

I too got a radius of 5.364, which would yield 90.379 which I believe
is close to what nikki derived, somewhere one of us lost some
significant digits in rounding (probably mine)