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 Chord Harmonics (Posted on 2005-01-11)
Four chords of a circle are arranged in such a way that they form a quadrilateral shape, the length of the chords are as follows.

6cm, 7cm, 8cm and 9cm.

what is the area of the circle that will intersect all of the points?

 No Solution Yet Submitted by Juggler Rating: 4.0000 (3 votes)

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 A fuzzy solution | Comment 7 of 9 |

Four chords are of length 6,7,8 & 9 cm

A diameter is longest chord in a circle. This means 9 cm chord will always be diameter.

SO a fuzzy result would be : 3.14 x (9/2)raise-to-2

= ~ 63.64 sq cms.

 Posted by Infiniti on 2005-02-03 07:24:48
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