A Lotto bet is picking 6 numbers out of 49 -- if you pick the correct combination, you get the jackpot!
If N persons play, there will be many repeats, since it's highly probable that some combinations will be chosen by two persons or more. (This is known as the "birthday paradox".)
What's the expected number of DIFFERENT combinations that will be chosen, if N persons play? (Assume these persons pick their combinations totally randomly.)
(In reply to A simpler way of getting to solution
by Steve Herman)
I'm having a little trouble seeing why the probability that nobody wins
is 1-(D/C) (which is the same as saying the Expected # of
distinct picks is equal to the probability of someone winning *
C). Could you explain your reasoning? Thanks!