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Given positive, integer N, what does this algorithm produce?
```let S and D = N
repeat
let D = ⌊D/2⌋
subtract D from S
until D=0
produce S as the result```
Note: ⌊x⌋ represents the integer part of x.

For non-programmers: start with a positive, integer number (say, 19). Divide it by 2, discarding remainders, until you get to 0. (In this case, you'd get 9, 4, 2, and 1.) Sum all the quotients. (9+4+2+1=16.) Subtract the sum from the original number. (19-16=3.) What's the result?

 See The Solution Submitted by e.g. Rating: 3.7143 (7 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
 Solution | Comment 6 of 9 |
Didn't read any of the other solutions yet, but it appears to be the number of "1"s in the binary representation of N.  In binary, dividing by 2 is just a shift to the right.  If the right most digit is a 1, lop it off and add 1 to the result.
 Posted by Larry on 2005-01-14 23:42:34

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