 All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars  perplexus dot info  Zero to 150 in 2003 (Posted on 2002-11-29) Take the digits 2, 0, 0 and 3. Make equations equating to all the integers from 1 to 150 using these digits according to the following rules:-

a) The above digits are the only digits to be used and no other digits should appear anywhere in the equation (except on the side where the answer will be).

b) Use of any mathematical symbols are allowed.

c) The digits 2, 0, 0 and 3 should appear in the given order in the equation. e.g - 0 + 2 + 3 + 0 = 5 is not acceptable.

d) When using the mathematical symbols try using the most simplest forms as much as possible.

 See The Solution Submitted by Raveen Rating: 4.0526 (19 votes) Comments: ( Back to comment list | You must be logged in to post comments.) Some more | Comment 14 of 65 | 11 = (2 + 0!)! - 0! + 3!
12 = (2 + 0!)! - 0 + 3!
13 = (2 + 0!)! + 0! + 3!
14 = (2 + 0) (0! + 3!)
15 = {(2 + 0!)! - 0!} x 3 (there was a simpler solution, I dont remember!)
16 = 20 - 0! - 3 = 2(0! + 0!)³ (Looks nice:)
17 = 20 - 0 - 3
18 = 20 + 0! -3
19 =
20 = 20 + (0 x 3)
21 = (20 + 0!)/3

This is with the assumption that 0! = 1. I guess a lot of the other numbers can follow from this.

 Posted by Dulanjana on 2002-11-29 21:37:27 Please log in:

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