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 Zero to 150 in 2003 (Posted on 2002-11-29)
Take the digits 2, 0, 0 and 3. Make equations equating to all the integers from 1 to 150 using these digits according to the following rules:-

a) The above digits are the only digits to be used and no other digits should appear anywhere in the equation (except on the side where the answer will be).

b) Use of any mathematical symbols are allowed.

c) The digits 2, 0, 0 and 3 should appear in the given order in the equation. e.g - 0 + 2 + 3 + 0 = 5 is not acceptable.

d) When using the mathematical symbols try using the most simplest forms as much as possible.

 See The Solution Submitted by Raveen Rating: 4.0526 (19 votes)

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 No Subject | Comment 37 of 65 |
What about the subfactorial sign e.g-(!3 = 2). I dont know how it exactly works. I thinks its the number of derangements in somethinf (factorials are the arrangements)

And this is just for fun.

A = {a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,s,t,u,v,w,x,y,z,wet,send,as,queue,hog,cat,dog,you,2,0,0,3}

So n(A) = 37
 Posted by Dulanjana on 2002-12-05 15:24:26

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