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Zero to 150 in 2003 (Posted on 2002-11-29) Difficulty: 4 of 5
Take the digits 2, 0, 0 and 3. Make equations equating to all the integers from 1 to 150 using these digits according to the following rules:-

a) The above digits are the only digits to be used and no other digits should appear anywhere in the equation (except on the side where the answer will be).

b) Use of any mathematical symbols are allowed.

c) The digits 2, 0, 0 and 3 should appear in the given order in the equation. e.g - 0 + 2 + 3 + 0 = 5 is not acceptable.

d) When using the mathematical symbols try using the most simplest forms as much as possible.

See The Solution Submitted by Raveen    
Rating: 4.0526 (19 votes)

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Zero to 150 in 2003 | Comment 42 of 65 |
Well I don't believe that using sigma functions is valid for this class of problem. It was specifically disallowed for a problem I encountered many years ago called the "Four Fours Problem", where the goal was to get from 1 to as far as possible. The usual arithmetic operators were allowed, as were factorial, subfactorial and recurring decimal notation.

Within these constraints so far I have found solutions to 104 out of the 150 and my first gap is at 52. Can anybody help with that? I'd be happy to post my complete list to date if anyone wants it.
  Posted by Robin Gatter on 2003-01-09 23:05:56
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