(In reply to re: Simple solution
by Steve Herman)
"(a) using a 1/p coin, the probablity of head-tails is not equal to the probability of tails-heads, unless p = 2"
If you have a 1/3-coin, the probability of heads-tails is 1/3 * 2/3. The probability of tails-heads is 2/3 * 1/3, and multiplication is commutative, so the probability is 2/9 in either instance.
On the other hand, problem (b) is valid: "Any solution which includes tossing again does not satisfy the the requirement the "fixed finite number of times" requirement."
Posted by Charlie
on 2005-02-19 02:55:00